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10x^2=35x-30
We move all terms to the left:
10x^2-(35x-30)=0
We get rid of parentheses
10x^2-35x+30=0
a = 10; b = -35; c = +30;
Δ = b2-4ac
Δ = -352-4·10·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5}{2*10}=\frac{30}{20} =1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5}{2*10}=\frac{40}{20} =2 $
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